"A 2kg Toy Car Moves Along A Frictionless Surface With A Uniform Speed Of 6 M/S. What Is Its Kinetic Energy?, A. 3.6 J, B. 36 J, C. 366 J, D. 3660 J"

"A 2kg toy car moves along a frictionless surface with a uniform speed of 6 m/s. What is its kinetic energy?

a. 3.6 J
b. 36 J
c. 366 J
d. 3660 J"

 

Answer:

A 2kg toy that moves along a frictionless surface with a velocity of 6m/s will have a kinetic energy of b. 36J

Explanation:

To fully understand the question, we need to understand the concept of kinetic energy. Kinetic energy is the work that an object needs to possess in order for it to be in action or to accelerate. Technically, kinetic energy is the object's energy generated by its motion in a reference. The energy is gathered through its consistent acceleration and its magnitude until a change of velocity is done. The kinetic energy of an object will be set to 0 once it is put into rest; zero velocity.

The formula to get the Kinetic Energy is KE = \frac{1}{2}mv^2

To visualize the defiition of kinetic energy through its formula, imagine this. It is harder to pull something up because as height increases, the kinetic energy decreases. If you let go of the object, it goes down faster because kinetic energy is bigger as the heigh decreases. Why? Because as the object goes closer to the ground the velocity increases due to the rate of acceleration.

We will answer the problem in GRESA (Given, Required, Equation, Solution, Answer) format to easily catch up to the step-by-step procedures.

PROBLEM

A 2kg toy car moves along a frictionless surface with a uniform speed of 6 m/s. What is its kinetic energy?

GIVEN

m = 2 kg

v = 6 m/s

REQUIRED

KE = ?

EQUATION

KE=\frac{1}{2}mv^2

SOLUTION

Insert all of the given constant to its designated variable in the formula

KE=\frac{1}{2}mv^2\\\\KE=\frac{1}{2}(2 kg)(6 m/s)^2\\\\KE=\frac{1}{2}(2 kg)(36m^2s^2)\\\\KE=\frac{1}{2}(72J)\\)\\KE=36J

ANSWER

KE=36J/tex

The kinetic energy of the 2kg toy car along a frictionless surface would be 36 J.

Internal links you may visit to help you out regarding kinetic energy and potential energy:

brainly.ph/question/2146893

brainly.ph/question/233160

brainly.ph/question/77384

CODE:

9.22.4.2.


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